How do you translate to an algebraic expression 6 less than x cubed?

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Answer 1 · 2015-07-02T18:08:25

#x^3-6#

For problems like this, it's good to be break up the information and visualize how it fits in together.

So we're told we have a #6#. We're also told we have an #x^3# (x cubed).

The question tells us that there is #6# less than #x^3#. That means that #6# is always being taken away from #x^3#, being subtracted from it.

Therefore, the expression would be:
#x^3-6#
which you could make into a function:
#f(x)=x^3-6#

Answer 2 · 2015-07-03T17:27:34

#6# < #x^3#

This is an alternative way to interpret the question; as an inequality

We are told that we have #6# less than #x^3#

#6# less than #x^3#= #6# < #x^3# since "<" is the "less than" sign