Question

How do you solve `4sinxcosx=1`?

Answer 1

`x=pi/12+kp`i,
`x = (5pi)/12+kpi`

Explanation:

Use the trig identity:
`sin 2x = 2sin xcos x`
In this case,
`4sin xcos x = 2sin 2x = 1` =>
`sin 2x = 1/2`
Trig table and unit circle give 2 solutions:
a. `2x=pi/6 + 2kpi` -->
`x=pi/12 + kpi`.
b. `2x=(5pi)/6 + 2kpi`, -->
`x=(5pi)/12 + kpi`.