How do you factor #3x^2 +10xy -25y^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. Jul 6, 2015 #3x^2+10xy-25y^2 = (3x-5y)(x+5y)# Explanation: If #3x^2+10xy-25y^2# has factors with integer coefficients, then they will take the form: #3x^2+10xy-25y^2 = (3x+ay)(x+by)# #= 3x^2+(3b+a)xy+aby^2# Since #ab=-25#, the possible #(a, b)# values are: #(-25, 1)#, #(-5, 5)#, #(-1, 25)#, #(1, -25)#, #(5, -5)#, #(25, -1)# These give values for #3b+a# of: #-22#, #10#, #74#, #-74#, #-10#, #22# So choose #a=-5# and #b=5# to get the correct coefficient of #xy# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1616 views around the world You can reuse this answer Creative Commons License