Question

How do you complete the square for `8x^2 -160x + 560`?

Answer 1

Solve `y = 8x^2 - 160 + 560 = 0`

Explanation:

`y = 8(x^2 - 20x + 70) = 0`

`(x^2 - 20x + 100) = 100 - 70 = 30`

`(x - 10)^2 = 30` ->`(x - 10) = +- sqrt30`

`x = 10 +- sqrt30`