Question

How do you solve `ln(x + 5) - ln(3) = ln(x - 3)`?

Answer 1

I found `x=7`

Explanation:

You can use one rule of the logs:
`loga-logb=loga/b`
to get:
`ln((x+5)/3)=ln(x-3)`
take the exponential of both sides:
`e^(ln((x+5)/3))=e^(ln(x-3))`
that gives you (cancelling `ln` and `e`):
`(x+5)/3=x-3`
`x+5=3x-9`
`2x=14`
`x=7`