How do you factor #6r^3m^3-42r^2m^2+54rm-378#?

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Answer 1 · 2015-07-08T07:10:45

Factor out the GCF #6#. Then factor by grouping.

#6r^3m^3-42r^2m^2+54rm-378#

Factor out the GCF #6#.

#6(r^3m^3-7r^2m^2+9rm-63)#

Factor by grouping.

#6(r^3m^3-7r^2m^2)+(9rm-63)#

Factor out common terms for both groups.

#6(r^2m^2(rm-7))+(9(rm-7))#

Factor out the common term #(rm-7)#.

#6(r^2m^2+9)(rm-7)#