Question

How do you solve `9^(2x-1)=27^x`?

Answer 1

`color(blue)(x=2`

Explanation:

`9^(2x-1) = 3^(2.(2x-1)) = 3^(4x-2)`

`27^x = 3^(3x)`

Upon equating:

`3^(4x-2) = 3^(3x)`
Since the base is equal , we can equate the powers:

`4x-2 =3x`
`color(blue)(x=2`