f(g(x)) is the same as (f@g)(x)
So
f(g(4)) is the same as (f@g)(4)
But
(f@g)(x) = sqrt(1-3x^2)/(2x-8)
color(white)("XXXX")color(white)("XXXX")...or sqrt((1-3x^2)/(2x-8))
color(white)("XXXX")color(white)("XXXX")it's hard to guess the range of the root symbol
color(white)("XXXX")color(white)("XXXX")and doesn't make any difference in this case, since...
When x=4
color(white)("XXXX")we have an attempt to divide by zero
color(white)("XXXX")which is undefined.