How do you factor #6x^2-5x+1#?

1 Answer
Nghi N.
Jul 16, 2015

Factor #y = 6x^2 - 5x + 1#
y = (3x - 1)(2x - 1)

Explanation:

Use the new AC Method
Converted #y' = x^2 - 5x + 6.#
Factor pairs of ac = 6 -> (1, 6)(2, 3) -> This sum is 5 = -b.
p' = -2 and q' = -3
#p = -2/6 = -1/3# and #q = -3/6 = -1/2#

Factor form y = 6(x - 1/3)(x - 1/2) = (3x - 1)(2x - 1)

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