Question

How do you determine whether (0,1) is a solution to `y > 5/3x - 4`?

Answer 1

You fill in the values of `xandy` and see if this is correct
`x=0andy=1`

Explanation:

`1>5/3*0-4->1>0-4->1> -4`

This is correct, so `(0,1)` is a solution.