How do you simplify #(1/2 + 2/(5i)) + (1/20 - 1/(5i))#?

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Answer 1 · 2015-07-17T21:25:58

#11/20+1/(5i)#

#(1/2+2/(5i))+(1/20-1/(5i))#

We can remove the parenthesis:

#1/2+2/(5i)+1/20-1/(5i)#

Rearranging a bit:

#1/2+1/20+2/(5i)-1/(5i)#

We need to make the denominators of #1/2# and #1/20# alike and we can see that the denominators of #2/(5i)# and #-1/(5i)# are already alike.

#1/2*10/10=10/20#

So,

#1/2+1/20+2/(5i)-1/(5i)=10/20+1/20+(2-1)/(5i)#

#=11/20+1/(5i)#