How do you factor #3y^2 +y -16#?
1 Answer
Jul 17, 2015
Factor f(y) = 3y^2 + y - 16
Answer: not factorable
Explanation:
f(y) = 3y^2 + y - 16
D = 1 + 192 = 193. D is not a perfect square, then this function can't be factored.
