What is the equation of the oblique asymptote #f(x)=(x^2-x-2)/(x+1)#?

Question

1911 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-18T10:22:20

#f(x) = (x^2-x-2)/(x+1) = ((x-2)(x+1))/(x+1) = x-2#

So #f(x)# is a straight line (with excluded point #(-1,-3)#).

It has no asymptote.

#(x^2-x-2)/(x+1)#

#= (x^2+x-2x-2)/(x+1)#

#= (x(x+1)-2(x+1))/(x+1)#

#= ((x-2)(x+1))/(x+1) = x-2#

with exclusion #x != -1#