How do you solve #2^(3x+19) = 16^(x+8)#?

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Answer 1 · 2015-07-19T13:38:29

#color(blue)(x=-13#

#2^(3x+19)=16^(x+8)#

#16= 2^4#
Rewriting the expression:

#2^(3x+19)=2^(4.(x+8)#

#2^(3x+19)=2^(4x+32)#

Now we can equate the powers:

#3x+19 = 4x+32#

#x= = 19-32#
#color(blue)(x=-13#