How do you graph $y= -3* abs(x+1)+4$ ?

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Answer 1 · 2015-07-19T23:42:01

Actually there are two graphs to be made

(1) $x>=-1->x+1>=0$ :
$=-3(x+1)+4=-3x+1$

(2) $x<-1->x+1<0$ but the absolute turns it around:
$=-3*(-(x+1))+4=3(x+1)+4=3x+7$

They meet at $(-1,4)$
graph{-3|x+1|+4 [-10, 10, -5, 5]}

How do you graph y= -3* abs(x+1)+4y= -3* abs(x+1)+4?