What is #cos (arcsin (5/13))#?

2 Answers
Jul 21, 2015

#12/13#

Explanation:

First consider that : #epsilon=arcsin(5/13)#

#epsilon# simply represents an angle.

This means that we are looking for #color(red)cos(epsilon)!#

If #epsilon=arcsin(5/13)# then,

#=>sin(epsilon)=5/13#

To find #cos(epsilon)# We use the identity : #cos^2(epsilon)=1-sin^2(epsilon)#

#=>cos(epsilon)=sqrt(1-sin^2(epsilon)#

#=>cos(epsilon)=sqrt(1-(5/13)^2)=sqrt((169-25)/169)=sqrt(144/169)=color(blue)(12/13)#

Dec 6, 2015

#12/13#

Explanation:

First, see #arcsin(5/13)#. This represents the ANGLE where #sin=5/13#.

That is represented by this triangle:

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Now that we have the triangle that #arcsin(5/13)# is describing, we want to figure out #costheta#. The cosine will be equal to the adjacent side divided by the hypotenuse, #15#.

Use the Pythagorean Theorem to determine that the adjacent side's length is #12#, so #cos(arcsin(5/13))=12/13#.