Question

How do you solve `2.5 = ln(x)`?

Answer 1

`x=e^{2.5}approx 12.1825`

Explanation:

`log_{b}(c)=d` is equivalent to `b^{d}=c`

Since `ln(x)=log_{e}(x)`, `ln(x)=2.5` is equivalent to `e^{2.5}=x`