Question

For `g(t)=t^3 +3`; how do you find g(1),g(-5),and g(0)?

Answer 1

A variable like `t` is a kind of 'place holder' for any value or expression.

Put `1` in place of `t` to find: `g(1) = 4`

Similarly `g(-5) = -122` and `g(0) = 3`

Explanation:

Put `color(red)(1)` in place of `t` to find:

`g(color(red)(1)) = (color(red)(1))^3+3 = 1+3 = 4`

Putting `color(red)(-5)` in place of `t` we find:

`g(color(red)(-5)) = (color(red)(-5))^3+3 = -125+3 = -122`

Putting `color(red)(0)` in place of `t` we find:

`g(color(red)(0)) = (color(red)(0))^3+3 = 0+3 = 3`

You can put expressions in place of `t` too.

For example,

`g(color(red)(2x+1)) = (color(red)(2x+1))^3+3`

`= (8x^3+12x^2+6x+1)+3`

`= 8x^3+12x^2+6x+4`