Question

How do you find the coordinates of the vertex for the parabola `f(x) x^2 + 3`?

Answer 1

Make sure the square `=0` and see what `y` you get.

Explanation:

This one is easy because when `x=0->x^2=0`
This will give an `f(x)=3`

So the vertex `=(0,3)`
graph{x^2+3 [-10.08, 9.92, -1.28, 8.72]}