How do you solve #log x^3 + log 8 =3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer GiĆ³ Aug 4, 2015 I found: #x=5# Explanation: Supposing your logs with base #10# and considering the property of the sum of logs you can write: #log_10(x^3*8)=3# #8x^3=10^3# #x^3=10^3/8# taking the cube root on both sides you get: #root3(x^3)=root3(10^3/8)# So: #x=10/2=5# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3554 views around the world You can reuse this answer Creative Commons License