Why is the #C_6H_8# molecule different from benzene with respect to resonance?
1 Answer
Benzene has two important equivalent resonance contributors, while any other
Explanation:
There are many molecules with the formula
Benzene
Benzene has two equivalent resonance contributors, neither of which involves the separation of charge.
(from chemistry.stackexchange.com)
Hexa-1,3,5-triene
Hexa-1,3,5-triene has only one important resonance contributor.
(from www.chemsynthesis.com)
Any other contributor we might draw has a separation of charge. For example,
Cyclohexa-1,3-diene
Cyclohexa-1,3-diene is an "almost"-benzene.
But it is still a "linear" diene.
Like hexa-1,3,5-triene, it has only one important resonance contributor, with any other contributors having separation of charge.