Question

What volume of ice would you have if you had `"1 L"` of water that froze?

Answer 1

Density is equal to mass divided by volume. So volume would be equal to mass divided by density. Assuming mass stays at 1 liter which is 1000 grams and the density of ice is about 0.934 g/ml than the volume would be 1070.66 ml or
1.07066 liters.

Answer 2

The volume of ice would be `"1091 cm"^3`.

Explanation:

The density of water at 0 °C is `"0.9998 g/cm"^3`.

If you had 1 L of water at that temperature, its mass would be

`M = 1000 color(red)(cancel(color(black)("cm"^3))) × "0.9998 g"/(1color(red)(cancel(color(black)("cm"^3)))) = "999.8 g"`

The density of ice at 0 °C is `"0.9162 g/cm"^3`.

The volume of 998.8 g of ice at 0 °C is

`V = 998.8 color(red)(cancel(color(black)("g"))) × ("1 cm"^3)/(0.9162 color(red)(cancel(color(black)("g"))))= "1091 cm"^3`