Question

How do you graph `f(x) = 4^x + 2`?

Answer 1

Plot points according to the formula, making sure to use both positive and negative values for `x`. Most negative values for `x` will not result in whole numbers for the `y` values. The graph is a vertical asymptote.

Explanation:

Substitute `y` for `f(x)`.

`y=4^x+2`

Determine several points using the equation, making sure to include negative as well as positive values for `x`.

Points
`x=-3, y=2.0156`
`x=-2, y=2.0625`
`x=-1, y=2.25`
`x=0, y=3`
`x=1, y=6`
`x=2, y=18`
`x=3, y=66`

Plot your points. The graph will be an asymptote.

graph{y=4^x+2 [-14.24, 14.23, -7.11, 7.12]}