Question

How do you graph `(x-3)^2 + (y-2)^2 = 9`?

Answer 1

It's a circle with centre `(3,2)` and radius `3`.

Explanation:

The equation of a circle can be expressed as:
`(x-a)^2 + (y-b)^2 = R^2`
where `(a,b)` is the co-ordinate of the centre of the circle and `R` is the radius.

Here `a = 3` and `b = 2`, so it's a circle with centre `(3,2)` and radius `sqrt(9) = 3`.

graph{(x-3)^2+(y-2)^2 = 9 [-6 10, -2, 6]}