How do you solve # 5^(n-1)=1/25#?

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Answer 1 · 2015-08-17T06:41:55

#color(blue)(n=-1#

#5^(n-1)=1/25#

#1/25=1/5^2#

As per property
#color(blue)(1/a=a^-1#

So,#1/5^2 = 5^-2#

#5^(n-1)=1/25#

#5^(n-1)=5^-2#
Since the bases are same we equate the exponents

#n-1=-2#

#color(blue)(n=-1#