If 4(x-y^3)-xy=16 ,evaluate dy/dx at the point (2,3)?

1 Answer
Aug 17, 2015

(dy)/dx|_(x=2,y=3) = 1/110

Explanation:

4(x-y^3)-xy = 16
Differentiate with respect to x:
4(1-3y^2(dy)/dx)-y-x(dy)/dx = 0
(dy)/dx = (4-y)/(x+12y^2)

(dy)/dx|_(x=2,y=3) = 1/110