Question

How do you solve `6n^2-18n-18=6` by factoring?

Answer 1

Let's start by dividing everything by `6`

Explanation:

`->n^2-3n-3=1`

Now subtract `1` on both sides to get an `=0` equation
`->n^2-3n-4=0`

Now we factor, by finding factors of `-4` that add up to `-3`
These are `-4and+1`
`->(n-4)(n+1)=0`

Two solutions:
`(n-4)=0->n=4or(n+1)=0->n=-1`