How do you solve #4< -z -4 < 11#?
1 Answer
Explanation:
There are two inequalities here.
Firstly, let's solve them. Secondly, we will combine them into a resulting inequality for
-
#4 < -z - 4#
To solve this inequality for#z# , add#z# to both sides of equation and then subtract#4# from both sides.
The first transformation will bring positive#z# to the left side instead of negative in the right, getting
#z+4 < z-z-4#
#z+4 < -4#
The second transformation will get rid of#4# on the left:
#z+4-4 < -4-4#
#z < -8# -
#-z-4 < 11#
To solve this inequality for#z# , add#z# to both sides of equation and then subtract#11# from both sides.
The first transformation will bring positive#z# to the right side instead of negative in the left, getting
#z-z-4 < z+11#
#-4 < z+11#
The second transformation will get rid of#11# on the right:
#-4-11 < z+11-11#
#-15 < z# or, equivalently,#z > -15#
So, we have two conditions on
We can combine them into one: