Question #0dd83

2 Answers
Aug 21, 2015

#x = 28/3#

Explanation:

#-log3(x-9)=0#
#log3(x-9)=0#
#Rightarrow 3(x-9) = 1#(since #log 1 = 0# regardless of base)
#x-9 = 1/3#
#x = 28/3#

Aug 21, 2015

If the intended question is: Solve #-log_3(x-9)=0#, then the solution is #x=10#

Explanation:

#-log_3(x-9)=0# if and only if #log_3(x-9)=0#

Change to exponential form: #(x-9) = 3^0#.

So #x-9 = 1#, and #x = 10#.