Question

What is the period and frequency for `sin(2pi t / 5)`?

Answer 1

period of `sin((2pi)/5t) = 5`

frequency of `sin((2pi)/5t) = 1/5`

Explanation:

`sin(theta)` has a period of `2pi` relative to `theta`

`rArr sin((2pi)/5t)` has a period of `2pi` relative to `(2pi)/5t`

`rArr Sin((2pi)/5t)` has a period of `(2pi)/((2pi)/5) = 5` relative to `t`

frequency is the reciprocal of period