How do you prove #cos(2x) = [cos(x)]^2 - [sin(x)]^2# and #sin(2x) = 2sin(x)cos(x)# using Euler's Formula: #e^(ix) = cos(x) + isin(x)#?
1 Answer
Aug 25, 2015
Use Euler's Formula to evaluate
Explanation:
Equate real and imaginary parts to get: