Question

A grocer has two kinds of nuts, one that costs $5.00 per kilogram and another that costs $5.40 per kilogram. How many kilograms of each type of nut should be mixed in order to have 40 kg of a mixture worth $5.25 per kilogram?

Answer 1

`22 2/9` kgm of more expensive nuts and

`17 7/9` kgm of cheaper nuts.

Explanation:

Let the weight of the more expensive nuts be `N`
then
`color(white)("XXXX")500(40-N) + 545(N) = 525*40`

`rarrcolor(white)("XX")20000-500N+545N = 21000`

`rarrcolor(white)("XX")45N = 1000`

`rarrcolor(white)("XX")N=200/9 = 22 2/9`

Weight of the cheaper nuts: `40 - 22 2/9 = 17 7/9`