How do you simplify #tan t * cot t - sin^2 t#?

2 Answers
Sep 1, 2015

#cos^2t#

Explanation:

#tan tcot t= tan tx (1/tan t)=1#
#1-sin^2t=(sin^2 t+cos^2 t)-sin^2 t=cos^2t#

Sep 1, 2015

This problem requires some trigonometric identities,here,
1) cotx=1/tanx
2)#sin^2x#+#cos^2x#=1 or #cos^2x#=1-#sin^2x#

Explanation:

1) tan t*cot t -#sin^2t#* = tan t 1/tan t-#sin^2t#........(putting identity .1)
= 1-#sin^2t#................(putting identity .2)
= #cos^2t#
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I hope this helps :)