Question

What is the antiderivative of `e^-x`?

Answer 1

I found: `-e^-x+c`

Explanation:

Let us write:
`inte^-xdx=-e^-x+c` which is your antiderivative.

If you derive this result you'll get:
`d/(dx)(-e^-x+c)=-(-1*e^-x)+0=e^-x`