What is 2xy differentiated implicitly?

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Answer 1 · 2015-09-02T18:31:31

$y'=(2y)/(1-2x)$

The question does not specify with respect to what so I'll assume y is a function of x.

$y' = d((u.v))/dx=v.du/dx+u.dv/dx$

So:

$y'=2x.y'+y2.dx/dx$

$y'=2x.y'+2y$

$y'=(2y)/(1-2x)$

Answer 2 · 2018-07-20T14:43:59

The answer is $=-y/x$

The function is

$f(x,y)=2xy$

The partial derivatives are

$(delf)/(delx)=2y$

$(delf)/(dely)=2x$

Therefore,

$dy/dx=-((delf)/(delx))/((delf)/(dely))=-(2y)/(2x)=-y/x$