Question

How do you solve x+3y=-2, 2x-y=10?

Answer 1

The solutions for the system of equations is
`color(blue)(x=4, y=-2`

Explanation:

`x+3y=-2`, multiplying this equation by `2`
`color(blue)(2x)+6y=-4`......equation `1`

`color(blue)(2x)-y=10`.....equation `2`

Solving by elimination.

Subtracting equation `2` from `1` results in elimination of `color(blue)(2x`

`cancelcolor(blue)(2x)+6y=-4`
`-cancelcolor(blue)(2x)+y=-10`
`7y =-14`
`color(blue)(y=-2`

Finding `x` by substituting `y` in equation `1`
`x+3y=-2`
`x+3*(-2)=-2`
`x-6=-2`
`x=-2+6`
`color(blue)(x=4`