Question

How do you solve `e^(4x-1)=(e^2)^x`?

Answer 1

`x=1/2`

Explanation:

Well it is `e^(4x-1)=e^(2x)=>e^(4x-2x-1)=1=>e^(2x-1)=1=>2x-1=0=>x=1/2`