How do you differentiate #y = 10cosx#?

1 Answer
Sep 12, 2015

#d/dx10cosx=-10sinx#

Explanation:

From the rules of differentiation, the derivative of a constant times a function is the constant times the derivative of the function.
So #d/dx(10cosx) =10d/dx cosx#

Then from the rules of differentiation for trigonometric functions, the derivative of the cosine of a function is the negative sine of the function multiplied by the derivative of the function.
#therefore d/dxcosx = -sinx*d/dxx#

since x can be written as #x^1#, it is a polynomial function and so its derivative is the power times the function raised to1 less than the given power, that is
#d/dxx^1=1x^0=1#
Hence the overall answer is #d/dx10cosx=-10sinx#