How do you write #y-5 = 3/2 (x+4)# in standard form?

2 Answers
Sep 13, 2015

#3x-2y=-22#

Explanation:

Standard form for a linear equation is
#color(white)("XXXX")Ax+By=C#
#color(white)("XX")"with "A, B, C in ZZ, A>=0#

Given
#color(white)("XX")y-5=3/2(x+4)#
Multiply both sides by #3# (and simplify the right side)
#color(white)("XX")2y-10=3x+12#
Add 10 to both sides
#color(white)("XX")2y=3x+22#
Subtract #3x# from both sides
#color(white)("XX")-3x+2y=22#
Multiply both sides by #(-1)#
#color(white)("XX")3x-2y=-22#

Sep 13, 2015

#3x-2y=-22#=>standard form.

Explanation:

The equation of line in the standard form is:

#Ax + By = C#

where A is a positive integer, and B, and C are integers.

So in this case:

#y - 5 = 3/2(x + 4)# => multiply both sides by 2:

#2y - 10 = 3(x + 4)# => expand the right side:

#2y - 10 = 3x + 12# => rewrite as:

#3x + 12 = 2y - 10#=> subtract 2y from both sides:

#3x-2y+12=-10#=> subtract 12 from both sides:

#3x-2y=-22#=>standard form.