How do you multiply #8sqrt(3/3) * 8sqrt(3/3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Meave60 Sep 14, 2015 The answer is #64#. Explanation: #8sqrt(3/3)*8sqrt(3/3)# Reduce the fractions #3/3#. #sqrt(3/3)=sqrt (cancel 3^1/cancel 3^1) =sqrt1=1# #(8*1)*(8*1)=64# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1198 views around the world You can reuse this answer Creative Commons License