Question

How do you find the area of the region bounded by the two axes and the line y=4-3x?

Answer 1

`8/3`

Explanation:

graph{4-3x}

It's a triangle with 90 degree angle, so `p=(ab)/2`; intersection of the given line with y-axis is `a` and with x-axis is `b`.
`x=0, y=4 => a=4`
`y=0, 0=4-3x, x=4/3 => b=4/3`
`P=(4 * 4/3)/2=8/3`