Question

How do you write `y = (4x + 1)(2x − 3)` in standard form?

Answer 1

`y= 8(x-5/8)^2 -49/8`

Explanation:

It is `y= 8x^2-10x-3`

`=8(x^2 -(5x)/4)-3`

`= 8 (x^2 -(5x)/4 +25/64-25/64) -3`

`= 8 (x-5/8)^2 -3-25/8`

`= 8(x-5/8)^2 -49/8`