Question

How do you solve `log_2 (x+2) - log_2(x) =8`?

Answer 1

I found: `x=2/255=0.007843`

Explanation:

You can use first a rule of the log that says:
`logx-logy=log(x/y)`
and get:
`log_2[(x+2)/x]=8`
Then you use the definition of log to get:
`(x+2)/x=2^8`
rearranging:
`x+2=256x`
`255x=2`
`x=2/255=0.007843`