Question

How do you factor `4x^2-152x+690=0`?

Answer 1

Refer to explanation

Explanation:

Hence it is trinomial we find its roots as follows

`x_(1,2)=(-b^2+-sqrt(b^2-4ac))/(2a)`

where `a=4 , b=-152 , c=690` hence we have that

`x_1=1/2*(38-sqrt(754))` and `x_2=1/2*(38+sqrt(754))`

Hence it can be factor as follows

`4x^2-152x+690=(x-x_1)*(x-x_2)`