Question

Question #3979d

Answer 1

`MM=m/(PV)RT`

Explanation:

We can modify the ideal gas law expression `PV = nRT` by replacing the number of mole by `n =m/(MM)` therefore, `PV=m/(MM) RT` .

Then the molar mass could be calculated from `MM=m/(PV)RT`.

You plug in your numbers, you will find the answer.

`m=0.4g`
`P=100xx10^3cancel(Pa)xx(1atm)/(10^5cancel(Pa)) = 1 atm`
`V=227 cm^3 = 0.227 L`
`T=27^@ C = 300K`

`MM=(0.4g)/(1cancel(atm)xx227xx10^(-3)cancel(L))xx0.08206 (cancel(L)*cancel(atm))/(mol*cancel(K))xx300cancel(K)`

`MM=43.38 g/(mol)`