Question #3979d

1 Answer
Sep 20, 2015

MM=m/(PV)RT

Explanation:

We can modify the ideal gas law expression PV = nRT by replacing the number of mole by n =m/(MM) therefore, PV=m/(MM) RT .

Then the molar mass could be calculated from MM=m/(PV)RT.

You plug in your numbers, you will find the answer.

m=0.4g
P=100xx10^3cancel(Pa)xx(1atm)/(10^5cancel(Pa)) = 1 atm
V=227 cm^3 = 0.227 L
T=27^@ C = 300K

MM=(0.4g)/(1cancel(atm)xx227xx10^(-3)cancel(L))xx0.08206 (cancel(L)*cancel(atm))/(mol*cancel(K))xx300cancel(K)

MM=43.38 g/(mol)