How do you write #d^2-12d+32# in factored form?

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Answer 1 · 2015-09-20T16:39:25

#color(blue)((d-4)(d-8) # is the factorised form of the expression.

#d^2−12d+32#

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like #ad^2 + bd + c#, we need to think of 2 numbers such that:

#N_1*N_2 = a*c = 1* 32 = 32#

AND

#N_1 +N_2 = b = -12#

After trying out a few numbers we get #N_1 = -8# and #N_2 =-4#

#(-8)*(-4) = 32# and #(-8)+ (- 4)= -12#

#d^2−12d+32 = d^2−8d -4d+32 #

#=d(d-8) -4(d-8)#

#color(blue)((d-4)(d-8) # is the factorised form of the expression.