Question

The perimeter of a rectangle is 40. The width is four less than 5 times the length. How do you find the dimensions of the rectangle?

Answer 1

I found `16 and 4`

Explanation:

Considering your rectangle:

The perimeter `P` is the sum of the 4 lengths:
`P=40=W+W+L+L=2W+2L`
and:
`40=2(5L-4)+2L`
`40=10L-8+2L`
`L=48/12=4`
So: `W=5*4-4=16`