Question

What are the real zeros of `f(x) = 3x^6 + 1`?

Answer 1

Refer to explanation

Explanation:

There aren't any. Let assume that there is value `a` for which
`f(a)=0` hence

`3*a^6+1=0=>a^6=-1/3`

which is impossible because the first part is always positive and the second is negative.