Question

How do you factor `5x^2-5/2x+1/5=0`?

Answer 1

`x_1 =2/5`
`x_2=1/10`

Explanation:

quadratic formula :
`x_1,_2 =(-b+- sqrt(b^2-4ac))/(2a)`

simplify equation by multiplying both sides with 10
`50x^2-25x+2=0`

here, a=50, b=-25, c=2

using quadratic formula
`x_1,_2=(-(-25)+- sqrt((-25)^2-50*2))/(2*50)`

After solving,
`x_1=(25+ sqrt(225))/(100) = 2/5`
`x_2=(25- sqrt(225))/(100) = 1/10`