How do you rationalize the denominator and simplify #10/root3(7)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Alan P. Sep 28, 2015 #10/7root(3)(49)# Explanation: #10/root(3)(7)# #color(white)("XXX")=10/root(3)(7)*root(3)(7)/root(3)(7)*root(3)(7)/(root(3)(7)# #color(white)("XXX")=(10(root(3)(7))^2)/((root(3)(7))^3)# #color(white)("XXX")=(10(root(3)(7^2)))/(7)# #color(white)("XXX")=(10(root(3)(49)))/7# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1316 views around the world You can reuse this answer Creative Commons License